Manually handle the submission

Hi ODK Devs,

I have ODK collect submitting to my server. What I want is to manage the
submission in my own way without aggregator. Is there a way I can do this?
My application is running on Django-python. Is there an easier way I can
do this with django? Is there an aggregator like implementation of Django?
What is the format or/and method of request that collect sends to the
submission URL and What response does it expect?

Thank you,
Kenneth

The ODK tools mostly follow the OpenRosa 1.0 API

https://bitbucket.org/javarosa/javarosa/wiki/OpenRosaAPI

Waylon

··· On Tue, May 15, 2012 at 11:25 PM, Aleister Matovu wrote: > Hi ODK Devs, > > I have ODK collect submitting to my server. What I want is to manage the > submission in my own way without aggregator. Is there a way I can do this? > My application is running on Django-python. Is there an easier way I can do > this with django? Is there an aggregator like implementation of Django? What > is the format or/and method of request that collect sends to the submission > URL and What response does it expect? > > Thank you, > Kenneth

Thank you

Apparently rapidsms-xforms https://github.com/nyaruka/rapidsms-xforms can
do just what I want to do.
Kenneth

··· On Wed, May 16, 2012 at 10:01 AM, W. Brunette wrote:

The ODK tools mostly follow the OpenRosa 1.0 API

https://bitbucket.org/javarosa/javarosa/wiki/OpenRosaAPI

Waylon

On Tue, May 15, 2012 at 11:25 PM, Aleister Matovu kbonky@gmail.com wrote:

Hi ODK Devs,

I have ODK collect submitting to my server. What I want is to manage the
submission in my own way without aggregator. Is there a way I can do
this?
My application is running on Django-python. Is there an easier way I
can do
this with django? Is there an aggregator like implementation of Django?
What
is the format or/and method of request that collect sends to the
submission
URL and What response does it expect?

Thank you,
Kenneth

Hi aleister, http://formhub.org / http://github.com/modilabs/formhub is a
django aggregate implementation, except we really emphasize the xlsform
tool, and make that the user input rather than xforms. Have a look.

Prabhas Pokharel
3479487654
@prabhasp

··· On May 16, 2012 3:08 AM, "Kenneth Matovu" wrote:

Thank you

Apparently rapidsms-xforms https://github.com/nyaruka/rapidsms-xforms
can do just what I want to do.
Kenneth

On Wed, May 16, 2012 at 10:01 AM, W. Brunette wbrunette@gmail.com wrote:

The ODK tools mostly follow the OpenRosa 1.0 API

https://bitbucket.org/javarosa/javarosa/wiki/OpenRosaAPI

Waylon

On Tue, May 15, 2012 at 11:25 PM, Aleister Matovu kbonky@gmail.com wrote:

Hi ODK Devs,

I have ODK collect submitting to my server. What I want is to manage the
submission in my own way without aggregator. Is there a way I can do
this?
My application is running on Django-python. Is there an easier way I
can do
this with django? Is there an aggregator like implementation of Django?
What
is the format or/and method of request that collect sends to the
submission
URL and What response does it expect?

Thank you,
Kenneth

Thank you
Kenneth

··· On Wed, May 16, 2012 at 3:24 PM, Prabhas Pokharel < prabhas.pokharel@gmail.com> wrote:

Hi aleister, http://formhub.org / http://github.com/modilabs/formhub is a
django aggregate implementation, except we really emphasize the xlsform
tool, and make that the user input rather than xforms. Have a look.

Prabhas Pokharel
3479487654
@prabhasp
On May 16, 2012 3:08 AM, "Kenneth Matovu" kbonky@gmail.com wrote:

Thank you

Apparently rapidsms-xforms https://github.com/nyaruka/rapidsms-xforms
can do just what I want to do.
Kenneth

On Wed, May 16, 2012 at 10:01 AM, W. Brunette wbrunette@gmail.comwrote:

The ODK tools mostly follow the OpenRosa 1.0 API

https://bitbucket.org/javarosa/javarosa/wiki/OpenRosaAPI

Waylon

On Tue, May 15, 2012 at 11:25 PM, Aleister Matovu kbonky@gmail.com wrote:

Hi ODK Devs,

I have ODK collect submitting to my server. What I want is to manage
the
submission in my own way without aggregator. Is there a way I can do
this?
My application is running on Django-python. Is there an easier way I
can do
this with django? Is there an aggregator like implementation of
Django? What
is the format or/and method of request that collect sends to the
submission
URL and What response does it expect?

Thank you,
Kenneth